3/31/2021 0 Comments Rectangular Glass Slab Experiment
The first case works OK, since if theta1 0 then sin(theta1) 0 and x0.This is physically plausible, for if the light ray is perpendicular then it does not change direction.This sounds correct to me since if the light ray approaches the slab almost parallel then after refracting back to air it should come out almost parallel, causing a lateral shift of exactly d.
I have checked glasss refraction index and it lies in the range 1.5 - 1.9. Physically, due to total internal reflection, the light will not exit in the air on the other side. This will happen at angles that are not close to 90 degrees but around 40 degrees for glass. So there is no physical meaning to the discussion of incident angles near 90 degrees. If the light starts outside the slab with an angle less than 90 degrees, the light inside the slab will have an angle less than the critical angle and some light will come all the way through to the other side. I agree that theta2 cannot get close to 90 degrees - but I never claimed that. This is physically reasonable because you require x to be zero when n1 as there is then no glass slab to deflect the beam. If you want more validation, though, youll just need to double-check your calculations, or reproduce them inside a bigger framework which you trust more. Because for that, the ray after refraction from the first surface must travel obliquely i.e. This is just hypothetical and we cant prove this practically. Not the answer youre looking for Browse other questions tagged optics geometric-optics or ask your own question.
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